Analog Lab Report 3

Part 1a

  1. Open the window. 
  2. Get the sponge wet. 
  3. Turn on the soldering iron. 
  4. If it reaches the temperature, when the iron touches the wet sponge, it should make some sounds. 
  5. In order to clean the tip of soldering iron, rub it on the sponge. 

Part 1b

  1. Switch the soldering iron off. 
  2. Clean the tip of the soldering iron by rubbing it on the sponge.
  3. Close the window before it gets too cold. 

Part 2a

You need to check if the two wires are in the right place. It is different for measuring the voltage from the current. 

Part 2b

Measured Voltage: 8.31V

Power = (V/R) * V = 8.31 ^ 2 / R < 0.25 W

8.31 ^ 2 / 0.25 < R

R > 276.22 Ω

Therefore, the smallest should be 330 Ω. But for safety, I will go for the next smallest one, which is 470 Ω.

The measured current is 0.018A. The power should be 8.31V * 0.018A = 0.15W, which is well below the upper limit. 

Part 2c

I2 = 8.31V / 1000 Ω = 0.00831A

I3 = 8.31V / 1000 Ω = 0.00831A

I4 = 8.31V / 2200 Ω = 0.00378A

I5 = 8.31V / 3300 Ω = 0.00252A

I1 = I6 = 0.00831A + 0.00831A + 0.00378A + 0.00252A = 0.02292A

Measured value:
I1 = I6 = 0.019A
I2 = 0.008A
I3 = 0.008A
I4 = 0.004A
I5 = 0.002A

Leave a comment

Design a site like this with WordPress.com
Get started